Raymond B. answered 04/24/22
Math, microeconomics or criminal justice
area of the circle = pi(r)^2 where r= the circle's radius
pi(2r) = x= circumference of the circle
r= x/2pi
area of the circle = pi(x/2pi)^2 = (x^2)/4pi
area of the square = a^2
where 4a = 4-x
= perimeter of the square
and where a= one side of the square
a= (4-x)/4 = 1-x/4
(1-x/4)^2 =1 - x/2 + (1/16)x^2 = area of the square
total area = A= (1/4pi)x^2 + 1 - (1/2)x + (1/16)x^2
take the derivative and set equal to zero
A'(x) = x/2pi -1/2 +x/8 = 0
(1/2pi + 1/8)x = 1/2
multiply by 8pi to remove fractions
(4 +pi)x = 4pi
x = 4pi/(4+pi)
= about 1.76 feet for the circle
4-x = 4-4pi/(4+pi)
= about 2.24 feet for the square
about 1 3/4 feet for the circle and about 2 1/4 feet for the square
exactly 4pi/(4+pi) feet for the circle
and exactly 4 - 4pi/(4+pi) feet for the square
minimum total area = about 1.76 times 2.24 = about 3.94 square feet
minimum total area = exactly [4pi/(4+pi)][4-4pi/(4+pi)] square feet