∫37 4ex - x dx = 4ex - 1/2x2 ]37 = 4e7 - 49/2 - (4e3 - 9/2) = 4(e7 - e3 - 5)
Cleor S.
asked 04/20/22Mathematics calculus
Find the area (in square units) of the region under the graph of the function f on the interval [3, 7].
f(x) = 4ex − x
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