∫-12 - x2 + 9 dx = - 1/3x3 + 9x ]-12 = -8/3 + 18 - (1/3 - 9) = 24
Cleor S.
asked 04/19/22Mathematics calclus
Find the area (in square units) of the region under the graph of the function f on the interval [−1, 2].
f(x)=-x^2+9
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