
Yefim S. answered 04/19/22
Math Tutor with Experience
d) Domain: x > 0
b) No y-intercept because x = 0 not in domain. x- intercept: y = 1/x + lnx = 0; no solution, no x-intercept
c) no any symmetry
a) f'(x) = - 1/x2 + 1/x = 0; - 1 + ,x = 0, x = 1
f''(x) = 2/x3 - 1/x2; f''(1) = 1 > 0. So, at x = 1 f(x) has local minimum: f(1) = 1