Mark M. answered 04/18/22
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
r = 8cosθ
So, r2 = 8rcosθ
x2 + y2 = 8x
(x2 - 8x) + y2 = 0
(x2 - 8x + 16) + y2 = 16
(x - 4)2 + (y - 0)2 = 42
This is the circle with center (4,0) and radius 4.