Raymond B. answered 04/15/22
Math, microeconomics or criminal justice
y' = -2x
Let (a,b) = (a, 4-a^2) = the point of tangency that passes through the point (3,0)
slope = -2a = (4-a^2)/(a-3)
-2a^2 +6a = 4 -a^2
a^2 -6a +4 = 0
a = 6/2 + (1/2)sqr(36-4(4))
a =3 +sqr5 or 3-sqr5
b= 4-a^2 = 4- 9-6sqr5 -5 = -10-6sqr5
or 4 -(3-sqr5)^2 = 4 -(9 -6sqr5 +5) = -10+6sqr5
the points of tangency are (3+sqr5, -10-6sqr5) and (3-sqr5, -10+sqr5)