Suppose x and y are both functions of t and y^2+36=8x^3 Find dy dt when x=2 , y=3 , and dx dt =−5.

Question

How do I do this

Thank you

Answer 1

y^2 +36 = 8x^3

2yy' = 24x^2)(x')

2(3)y' = 24(2)^2(-5)

y' = -240/6 = -40

y' = dy/dt = -40