10 [ 6 + 6x
(x) ] dx =
10 [ 6 + 6x3/2 ] dx = [ 6x + 6x5/2 / 5/2 ]10 = [ 6x + 12x2
(x) / 5 ]10 =
[ 6 * 1 + 12 * 12(1) / 5 ] - [ 6 * 0 + 12 * 02
(0) / 5 ] = [ 6 + 12 / 5 ] - [ 0 + 0 ] = 30 / 5 + 12 / 5 - 0 = 42 / 5.
Kelly B.
asked 04/12/22Evaluate the integral below.
10 (6+6x
x) dx
Evaluate the integral below.
Integral [0,1] (6+6x(sqrt(x)) dx
10 [ 6 + 6x
(x) ] dx =
10 [ 6 + 6x3/2 ] dx = [ 6x + 6x5/2 / 5/2 ]10 = [ 6x + 12x2
(x) / 5 ]10 =
[ 6 * 1 + 12 * 12(1) / 5 ] - [ 6 * 0 + 12 * 02
(0) / 5 ] = [ 6 + 12 / 5 ] - [ 0 + 0 ] = 30 / 5 + 12 / 5 - 0 = 42 / 5.
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