Mark M. answered 04/08/22
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
1 + tan2 θ = sec2 θ
1 + (3√10 / 20)2 = 1 / cos2 θ
Can you solve for cos θ and answer?
Tylar E.
asked 04/08/22
Mark M. answered 04/08/22
Mathematics Teacher - NCLB Highly Qualified
1 + tan2 θ = sec2 θ
1 + (3√10 / 20)2 = 1 / cos2 θ
Can you solve for cos θ and answer?
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