Mark M. answered 04/07/22
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫(from 0 to 1)f(x)dx = -10 and ∫(from 0 to 2)f(x)dx = -10
So, ∫(from 1 to 2)f(x)dx = ∫(from 1 to 0)f(x)dx + ∫(from 0 to 2)f(x)dx
= -∫(from 0 to 1)f(x)dx + (-10) = -(-10) - 10 = 0