Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a nine and then selecting a ten

Question

The probability of selecting a nine and then selecting a ten is? Round to three decimal places as needed.

Answer 1

(4/52) is the probability of getting a nine. There are 4 nines in the deck.

(4/51) is the probability of getting a ten since there are 4 tens in the reduced deck (the first card was not put back in the deck)

The fundamental counting principle says that we multiply the two probabilities to get

(4/52)(4/51)=16/2652, which is approx. 0.006