
Jon S. answered 04/02/22
Patient and Knowledgeable Math and English Tutor
status profit probability
failure 61-450 = -389 0.006
no failure 61 0.994
expected profit = -389 * 0.006 + 61 * 0.994 = 58.30
Kailey D.
asked 04/02/22A company estimates that 0.6% of their products will fail after the original warranty period but within 2 years of the purchase, with a replacement cost of $450.
If they offer a 2 year extended warranty for $61, what is the company's expected value of each warranty sold?
Jon S. answered 04/02/22
Patient and Knowledgeable Math and English Tutor
status profit probability
failure 61-450 = -389 0.006
no failure 61 0.994
expected profit = -389 * 0.006 + 61 * 0.994 = 58.30
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