Lim H.
asked • 04/02/22Find the limit of a function
- \lim_(x->((\pi )/(2))^(+))\ln ((2)/(\pi )x)tanx
- \lim_(x->1)(\sin ^(-1)((x)/(2))-(\pi )/(6))/(x-1)
- \lim_(x->0)(\sin ^(-1)(5x))/(tan^(-1)(2x))
I would like to know the detailed solution, please
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1 Expert Answer
Luke J. answered • 04/04/22
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Luke J.
The limit as x approaches zero of inverse sine of 5x divided by the inverse tangent of 2x
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04/04/22
Luke J.
Character limits restricted me from adding the last limit but for all the tutors on this site, those are the limits the student is struggling with. It took me a little bit to decipher the LaTeX notation used since it's the common form of LaTeX
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04/04/22
Luke J.
\lim_{x\to \frac{\pi}{2}^+}\left[\ln(\frac{2}{\pi x})\tan{x}\right]
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04/04/22
Luke J.
\lim_{x\to 1}\left[\frac{\sin^{-1}\left(\frac{x}{2}\right)-\frac{\pi}{6}}{x-1}\right]
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04/04/22
Luke J.
\lim_{x\to 0}\frac{\sin^{-1}{5x}}{\tan^{-1}{2x}}
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04/04/22
Luke J.
Recommended tip for #1, turn tan x into cot x in the denominator, than L'Hosiptal's Rule can be used effectively
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04/04/22
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Doug C.
I suggest rewriting the problems without all the backslashes and other likely Latex notation.04/02/22