Yefim S. answered • 03/30/22
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Δy = y(0.03) - y(0) = (e0.09 + 0.18) - 1 = 0.2742
y' = 3e3x + 6; y'(0) = 3 + 6 = 9; dy = y'(0)dx = 9·0.03 = 0.27
Pavel L.
asked • 03/30/22Compute the values of dy and Δy for the function y=e^3x+6x given x=0 and Δx=dx=0.03.
dy = [needed]
Δy = [needed]
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