Calculus Question

Question

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)

g(y) = y − 1

y2 − 3y + 3

 

y= ____

Answer 1

g(y) = (y-1) / (y²-3y+3)

g'(y) = [(y²-3y+3)(1) - (2y-3)(y-1)] / (y²-3y+3) = [-y²+2y] / (y²-3y+3)

g'(y) = 0 when -y²+2y = 0

-y(y-2) = 0

y = 0 or y = 2