Raymond B. answered 03/26/22
Math, microeconomics or criminal justice
p = 49 - 0.04q
R(q) = pq = 49q - 0.04q^2
R'(q) = 49 -0.08q = 0
q = 49/.08 = 612.5 is the revenue maximizing production level
p = 49-0.04(612.5) = 49 - 24.5 = $24.50 = revenue maximizing price
R(612.5) = 49(612.5)- 0.04(612.5)^2 = $15,006.25
or max R = pq = 24.5(612.5) = $15,006.25 = maximum revenue