Mark M. answered 03/24/22
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
First, Let x and y be in S. Show that x+y is also in S.
Since x and y are in S, Ax = λx and Ay = λy
So, A(x+y) = Ax + Ay = λx + λy = λ(x + y)
Therefore, x+y is in S.
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Second, Let x be in S and let c be a scalar (i.e., a real number). Show that cx is also in S
A(cx) = c(Ax) = c(λx) = λ(cx)
So, cx is in S.
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Third, 0 is in S since A(0) = λ(0)
Since S is closed under addition and scalar multiplication and since 0 is an element of S, S is a subspace of Rn.
Mark M.
03/24/22
Ruveshan N.
Thank you... Just one question... What do you mean by - First, Let x and y be in S. Show that x+y is also in S.03/24/22