Write an equation of the line that is parallel to 4x−10y=−90 and passes through point (27.5,−5).

Answer 1

4x -10y =-90 through (275, -5)

2x -5y = -45

y = 2x/5 with slope = 2/5 = .4

parallel lines all have slope = m = 2/5

y = mx +b

plug in slope and point to solve for b

-5 = .4(27.5) + b

b =- 5 -11 = - 16

line is y = 2x/5 - 16 in slope intercept form

or 2x -5y = 80 in standard form ax+by=c form with a=2, b=-5, c = 80

Answer 2

First, we need to find out the slope of the given line. To do this, we convert the equation to the slope/intercept form:

4x - 10y = -90

10y = 4x + 90

y = (2/5)x + 9

So the slope of the given line is 2/5. Now we can use the point-slope form of a line to create the equation of the new line:

(y + 5) = (2/5) * (x - 27.5)

5y + 25 = 2 * (x - 27.5)

5y + 25 = 2x - 55

5y = 2x - 80

y = (2/5)x - 16

So the answer is y = (2/5)x - 16.