Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point.

Question

it would be Y²-X² = 32 and the point is (4, 4√(3))

Y=

Answer 1

y² - x² = 32

2y(dy/dx) - 2x = 0

dy/dx = x/y = 4/ (4√3) = 1/√3 = √3/3 = slope of tangent line

Use the point slope form to get an equation of the tangent line.

Answer 2

The answer is y = [(x * sqrt(3)) / 3] + [8 * sqrt(3) / 3]. Please book a session to learn the steps.