The function must be continuous to be differentiable.
That means the first part of the function at x=2 has to = the second part at x=2, even though the first part isn't defined at exactly x=2.
5(2)+a(2)^4 = b(2)^2 - 3(2)
10 + 16a = 4b -6
16+16a = 4b
4 + 4a = b

Luke J.
And if it's differentiable, shouldn't the derivatives equal each other/approach each other as x approaches 2 from either side?03/20/22