Assuming adults are independent, then we can apply the binomial distribution to the number of adults who require eyesight correction.
This is simply given by P(X = 14) + P(X = 15) = 15C14 (0.79)^14(1-0.79)^1 + 15C15(0.79)^15 = 0.1453...
Jen A.
asked 03/19/22A survey showed that 79% of adults need correction for their eyesight. If 15 adults are randomly selected, find the probability that at least 14 of them need correction for their eyesight. Is 14 a significantly high number of adults requiring eyesight correction? The probability that at least 14 of the 15 adults require eyesight correction is?
Assuming adults are independent, then we can apply the binomial distribution to the number of adults who require eyesight correction.
This is simply given by P(X = 14) + P(X = 15) = 15C14 (0.79)^14(1-0.79)^1 + 15C15(0.79)^15 = 0.1453...
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