Daniel B. answered 03/20/22
A retired computer professional to teach math, physics
First to calculate all x satisfying
f(x) = g(x)
Let
h(x) = f(x) - g(x) = (x² - 3) - (4x + 9) = x² - 4x - 12
Then we set h(x) = 0, which gives the quadratic equation
x² - 4x - 12 = 0
There are two solutions to this quadratic equation:
x = -2, x = 6
The area enclosed by f(x) and g(x) is the absolute value of
the definite integral between -2 and 6
∫h(x)dx
Let H(x) = ∫h(x)dx =
∫(x² - 4x - 12)dx =
x³/3 - 2x² - 12x + C
Then the area enclosed by f(x) and g(x) is
|H(6) - H(-2)| = |(6³/3 - 2×6² - 12×6) - ((-2)³/3 - 2×(-2)² - 12×(-2))| = 85.33