
Yefim S. answered 03/17/22
Math Tutor with Experience
Area A = πr2; dA/dt = 2πrdr/dt = 2π·8inch·(- 3)inch/min = - 150.796 inch2/min
Eric D.
asked 03/16/22The radius of a circle is decreasing at a constant rate of 3 inches per minute. At the instant when the radius of the circle is 8 inches, what is the rate of change of the area? Round your answer to three decimal places.
Yefim S. answered 03/17/22
Math Tutor with Experience
Area A = πr2; dA/dt = 2πrdr/dt = 2π·8inch·(- 3)inch/min = - 150.796 inch2/min
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