
Dayv O. answered 03/14/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
another approach
is x=12/y
dx/dt=(-12/y2)(dy/dt)
which gives same answer
Ashley R.
asked 03/13/22A particle moves along a hyperbola xy = 12.
As it reaches the point (4, 3), the y-coordinate is decreasing at a rate of 3 cm/s. How fast is the x-coordinate of the point changing at that instant?
Dayv O. answered 03/14/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
another approach
is x=12/y
dx/dt=(-12/y2)(dy/dt)
which gives same answer
Mark M. answered 03/14/22
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
xy = 12
x(dy/dt) + y(dx/dt) = 0
So, dx/dt = -x(dy/dt) / y = -(4cm)(-3cm/sec) / (3cm) = 4 cm/sec
x is increasing at the rate pf 4 cm/sec
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