delta-rho/rho/temp = 3.5e-3 thus temp = delta-rho/rho /3.5e-3
delta-rho = 160-20 = 140
rho = 20
answer 2020C
Gabriel Z.
asked 03/08/22The filament of a light bulb has a resistance of 20.0 Ω at 20oC and 160 Ω when the light is on. Find the temperature of the filament when the light is on. (The temperature coefficient of resistivity is 3.50x10-3 oC-1.)
Group of answer choices
939oC
1120oC
1440oC
2020oC
2310oC
delta-rho/rho/temp = 3.5e-3 thus temp = delta-rho/rho /3.5e-3
delta-rho = 160-20 = 140
rho = 20
answer 2020C
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