Rebecca K. answered 03/08/22
BSE in Engineering Physics with 4 years Tutoring Experience
For each term, we must use the power rule d/dx(xn)=nxn-1
- y=3x^2 + 3√x - 5/x^2 = 3x2+ 3x1/2 -5x-2 => dy/dx=6x + 1.5x-1/2+10x-3
- y=(x^2-x)(√x) = x3/2-x1/2 => dy/dx=(3/2)x1/2+(1/2)x-1/2
- y=-6/4√3x =(-6/4√3)x-1 => dy/dx=(3/2√3)x-2
For the last we need the product rule: d/dx[f(x)g(x)]=f'(x)g(x)+g'(x)f(x)
y=(2x^2-1)^4 (3x^2+1)^2
f(x) = (2x2-1)4 f'(x)=4(2x2-1)3 * 4x
g(x) = (3x2+1)2 g'(x)=2(2x2-1) * 6x
dy/dx = (2x2-1)4 * 12x(2x2-1) + 8x(2x2-1)3 * (3x2+1)2