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r'(z)= -16e^(-4z) +4e^(-z)=4e^(-4z)(e^(3z)-4)=0, thus z=(1/3)*ln4=0.462.
r''(z=0.462)>0, thus at z=0.462, the minimum is achieved, which is r(z=0.462) = -1.8899
The maximum is achieved at z=0 or +∞, both has r(z)=0
Mariam A.
asked 03/07/22Consider the function on
.
Absolute Maximum value............ at =.............
Absolute Minimum value............. at =............
I just did the derivative which is r'(z)= -16e^(-4z) +4e^(-z)=0, but I don't know how to find z.
You are almost there!
r'(z)= -16e^(-4z) +4e^(-z)=4e^(-4z)(e^(3z)-4)=0, thus z=(1/3)*ln4=0.462.
r''(z=0.462)>0, thus at z=0.462, the minimum is achieved, which is r(z=0.462) = -1.8899
The maximum is achieved at z=0 or +∞, both has r(z)=0
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