Dilip D. answered 03/29/22
PhD in Physics with 32 years 0f teaching experience
Answer 0.45 J. [ for detailed explanation contact: [email protected]]
Brief explanation:
C =εoKA/d; Here d= 2 mm = 2x10-3 m; A = 1 m2. εo = 8.85x10-12 C2/N.m2. K = 5.6; Energy stored = CV2/2. Insert all these values and get energy stored in the capacitor = 0.892/2 = 0.45 Joules.