Since (0, -2) is on the graph, a(0)2 + b(0) + c = -2. So, c = -2.
Since (1,1) is on the graph, a + b - 2 = 1
Since (2,3) is on the graph, 4a + 2b - 2 = 3
So, a + b = 3 and 4a + 2b = 5
Solve for a and b.
Heena M.
asked 03/02/22Find coefficients a, b and c such that the graph of the function f(x) = ax2 + bx + c passes through the points (0, −2),(1, 1) and (2, 3).
Since (0, -2) is on the graph, a(0)2 + b(0) + c = -2. So, c = -2.
Since (1,1) is on the graph, a + b - 2 = 1
Since (2,3) is on the graph, 4a + 2b - 2 = 3
So, a + b = 3 and 4a + 2b = 5
Solve for a and b.
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