Find the slope and an equation of the tangent line to the graph of the function f at the specified point.

Question

F(x)= - (5/2)x^2 + 5x +5

and

what is the slope

and what is the Y equation

Answer 1

f(x) = -(5/2)x² + 5x + 5

f'(x) = -5x + 5

Slope of tangent at the point (-1, -5/2) is f'(-1) = 10

Equation of tangent line is y - (-5/2) = 10(x - (-1))

Answer 2

The value of the slope is x when F'(x) = 0

No point is specified.