Variables are separable so that
ln(y-1) = ∫(x+1) cos(x2 + 2x + π) dx and
the substitution z=x2 + 2x + π will yield a very easy integral.
Max P.
asked • 02/27/22Consider the differential equation ⅆy/ ⅆx=(y−1) (x+1) cos(x^2+2x+π).
Find the particular solution y= f(x) to the differential equation with initial condition f(0)= 5/2 .
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Doug C. answered • 02/27/22
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Doug C.
The constant has to be ln(3/2) because that is the result when you substitute 0 for x and 5/2 for y in the general solution.
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02/27/22
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Max P.
for the answer does it have to be ln 3/2 or can it just be 3/2?02/27/22