cosx can't be larger than 1, so the given equation (cosx = 35) has NO SOLUTION
If you mean cosx = 3/5, then sinx = √(1 - cos2x) = 4/5.
So, sin(2x) = 2sinxcosx = 2(3/5)(4/5) = 24 / 25
Hiepduc T.
asked 02/24/22If cos(x)=35 (in Quadrant-I), find
sin(2x)=
cosx can't be larger than 1, so the given equation (cosx = 35) has NO SOLUTION
If you mean cosx = 3/5, then sinx = √(1 - cos2x) = 4/5.
So, sin(2x) = 2sinxcosx = 2(3/5)(4/5) = 24 / 25
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