Gabriel Z.

asked • 02/22/22

AP Physics C e and M

Two point charges of 9μC and 4μC are placed a distance of 4 m apart. 


Two point charges of 9μC and 4μC are placed a distance of 4 m apart. 

Find the point, measured in meters from the 9μC charge, between the two charges where the force on the 5μC charge is 0? 

1 Expert Answer

By:

Gabriel Z.

Do I want to multiply each charge by the middle charge (5muC)? (8.99*10^9 * (9-10^-6)(5*10^-6)/(4-x)^2 = (8.99*10^9)* (4*10^-6)(5*10^-6)/(4-x)^2
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02/23/22

Gabriel Z.

Also How would I go about doing this problem, Calculate the magnitude of the force, in Newtons, on a positive 5μC charge at the midpoint between the two charges.
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02/23/22

Christopher B.

tutor
That setup looks good except for the denominator on the left side - the distance should just be x. Note that a bunch of this stuff cancels out - the k and the 5uC charge appear on both sides. For this other problem, they're asking about the force at x = 2m? For that, you can just calculate the force from each of the 2 point charges separately and add them together. Keep in mind that they will be in opposite directions.
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02/23/22

Gabriel Z.

Yes, they want to know the magnitude of the force on a 5muC charge at 2m
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02/23/22

Gabriel Z.

So for that would I do, (8.99*10^-6)* (9*10^-6)*(5*10^-6)/2^2+(8.99*10^-6)*(4*10^-6)(5*10^-6)/2^2 ?
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02/23/22

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