Find the integral of ∫ 2 secxtanx + 1/6x 𝑑𝑥

Answer 1

I will indicate my interpretation of your expression using parentheses.

If I got it wrong, can you rewrite the expression placing parentheses

in the correct positions?

∫(2sec(x)tan(x) + 1/(6x)) dx =

2∫sec(x)tan(x) dx + (1/6)∫1/x dx =

2∫sin(x)/cos²(x) dx + (1/6)ln(x) =

2/cos(x) + ln(x)/6