Marion J. answered 02/22/22
Qualified teacher who loves all types of Math
You will use the formula:
f'(a) = limh->0 (f(a+h) - f(a))/h
f'(1) = limh->0 ((1+h)/(1+h-3)-(1)/(1-3))/h
= limh->0 ((1+h)/(h-2)+(1/2))/h
= limh->0 3/(2h-4)
= -3/4
The slope of the tangent at f(1) is -3/4
f(1) = -1/2 so the tangent goes through the point (1, -1/2)
Plug these values into the formula for a straight line:
y - (-1/2) = -3/4(x - 1)
y = -3/4x + 1/4