Raymond B. answered 02/17/22
Math, microeconomics or criminal justice
s(t) = t^3 -13t^2 + 35t -200
take the derivative
v(t) = s'(t) = 3t^2 -26t + 35 = velocity at time t
s'(t) = 3t^2 -26t + 35 = 0
(3t -5)(t-7) = 0
t = 5/3 and 7 seconds
the velocity >0 when s'(t) > 0, when t>7 or t<5/3 seconds
velocity <0 when 5/3 < t < 7 seconds
b) moving in a positive direction in the intervals
(-infinity, 5/3) U (7, infinity)
c) moving in a negative direction in the interval (5/3, 7)
d) times when direction changes are 5/3 and 7 seconds