
Bradford T. answered 02/16/22
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
g(x) = 7/(x2+5) (I'm assuming this is what was meant)
g'(x) = -14x/(x2+5)2
Setting g'(x) to 0 and solving for x, x = 0
g(0) = 7/5 = 1.4
Using 2nd derivative test
g''(x) = 14(3x-5)/(x2+5)3
g''(0) = -0.56 <0 so g(0) = 1/4 is a maximum