Find the surface area of revolution about the y-axis of $y = 3 x + 1$ over the interval $0 \leq x \leq 2$

Question

Find the surface area of revolution about the y-axis of y=3x+1 over the interval 0≤x≤2

Marion J. · Accepted Answer

This revolution creates a cone with a radius of 2 and a height of 6.S = πr√(r2 + h2) = 39.7

Find the surface area of revolution about the y-axis of y = 3 x + 1 over the interval 0 ≤ x ≤ 2