
William W. answered 02/13/22
Experienced Tutor and Retired Engineer
If dh/dt= 19.21sin(1.7t + 0.3) − 16.32cos(1.7t + 0.3) then we can multiply both sides of the equation by dt and then integrate both sides to get:
The antiderivative of "dh" is just "h"
The antiderivative of "19.21sin(1.7t + 0.3) − 16.32cos(1.7t + 0.3)" is "-19.21/1.7cos(1.7t+0.3) - 16.32/1.7sin(1.7t + 0.3)" and then, of course, we add the constant C so:
h = -19.21/1.7cos(1.7t+0.3) - 16.32/1.7sin(1.7t + 0.3) + C
h = -11.3cos(1.7t + 0.3) - 9.6sin(1.7t + 0.3) + C
Using the fact that at t=0, h=25 we can solve for C:
25 = -11.3cos(1.7(0) + 0.3) - 9.6sin(1.7(0) + 0.3) + C
25 = -11.3cos(0.3) - 9.6sin(0.3) + C
25 = -11.3(0.95534) - 9.6sin(0.29552) + C
25 = -10.7953 - 2.8370 + C
C = 25 + 10.7953 + 2.8370 = 38.6323
So: h(t) = -11.30cos(1.70t + 0.30) - 9.60sin(1.70t + 0.30) + 38.63
To find the velocity when h = 45, first find "t" when h = 45:
The easiest way is to graph it. Doing so, you find that t = 1.423
Then plug in t = 1.423 into the velocity equation v(t) = dh/dt= 19.21sin(1.7t + 0.3) − 16.32cos(1.7t + 0.3)
Make sure your calculator is in radians.