Raymond B. answered 02/13/22
Math, microeconomics or criminal justice
T(h) = 300 -h/200
T'(h) = -1/200 = -0.005 degrees per second
T'(6) = -1/200 = -0.005 degrees per second
the rate of change is the same at any value of h
but the table of values is very different from the function T(h) = 300- h/200
T(878) = 300 -878/200 = 300-4.39 = 295.61 not 6
the function T(h) is a linear function, a straight line
the table of values is not a linear relationship.