Related rate problem:
1) Connect x and d: d = sqrt(902+ x2)
2) We know dx/dt = -25 ft/s and x = 21 ft at moment of interest
30 Differentiate eqn (1) in terms of t and apply chain rule:
dd/dt = 1/2 (902+x2)-1/2(2x) dx/dt
4) Substitute in to find dd/dt at x = 21 ft. (Note that you will get a negative rate)