y' = √3 - 2sinx = 0
sinx = √3/2
x = π/3 or 2π/3
Bella C.
asked 02/04/22Determine the point(s) (if any) at which the graph of the function has a horizontal tangent line.
y = √3 x + 2 cos(x), 0 ≤ x < 2𝜋
Step 1: Find the derivative y'
Step 2: Set y'=0 and solve for x
x1= (smaller x-value)
x2= (larger x-value)
Step 3: Find the y values
y' = √3 - 2sinx = 0
sinx = √3/2
x = π/3 or 2π/3
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