Kabir S. answered 02/01/22
UCB Graduate in Mathematics, 5+ years of experience tutoring Math
a)60pi*sec^2(pi/4) = 120pi ft/sec
b)60pi*sec^2(pi/3) = 240pi ft/sec
c) 60pi * limx-->pi/2(sec^2(x))
60pi(limx-->pi/2(sec(x)))^2
60pi(-inf)^2 = inf
Anikka C.
asked 02/01/22A patrol car is parked d = 60 feet from a long warehouse, as shown in the figure below. The revolving light on top of the car turns at a rate of 1/2 revolution per second. The rate at which the light beam moves along the wall is r = 60𝜋 sec2 𝜃
ft/sec.

(a) Find the rate r when θ is π/4.
(b) Find the rate r when θ is 𝜋/3
(c) Find the limit of r as θ→(π/2) – .
Kabir S. answered 02/01/22
UCB Graduate in Mathematics, 5+ years of experience tutoring Math
a)60pi*sec^2(pi/4) = 120pi ft/sec
b)60pi*sec^2(pi/3) = 240pi ft/sec
c) 60pi * limx-->pi/2(sec^2(x))
60pi(limx-->pi/2(sec(x)))^2
60pi(-inf)^2 = inf
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