Find the equation of the tangent line at x=4 (keep fractions in answer). f(x) = (6 x - 11)/(x^2 - 12)

Answer 1

f(4) = 13/4; f'(x) = (6x² - 72 - 12x² + 22x)/(x² - 12)² = (22x - 72 - 6x²)/(x² - 12)²; f'(*4) = - 80/16 = - 5;

Tangent line: y = f(4) + f'(4)(x - 4); y = 13/4 - 5(x - 4); y = - 5x + 93/4