Mike D. answered 01/29/22
Effective, patient, empathic, math and science tutor
f(1.5) ≈ f(1) +0.5 f'(1)
f'(1) = 2x1 + 0 = 2
f(1.5) ≈ 0 + 0.5 x 2 = 1
f(2) ≈ f(1.5) + 0.5 x f'(1.5)
f'(1.5) = 2 x 1.5 + 1 = 4
f(2) ≈ 1 + 0.5 x 4 = 3
Gahij G.
asked 01/29/22Let y=f(x) be the solution to the differential equation dy/dx=2x+y with initial condition f(1)=0. What is the approximation for f(2) obtained by using Euler's method with two steps of equal length, starting at x=1
Mike D. answered 01/29/22
Effective, patient, empathic, math and science tutor
f(1.5) ≈ f(1) +0.5 f'(1)
f'(1) = 2x1 + 0 = 2
f(1.5) ≈ 0 + 0.5 x 2 = 1
f(2) ≈ f(1.5) + 0.5 x f'(1.5)
f'(1.5) = 2 x 1.5 + 1 = 4
f(2) ≈ 1 + 0.5 x 4 = 3
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