f(2) = 1/2(2)2 - 1 = 1 ; P: (2 , 1)
f(2 + h) = 1/2(2 + h)2 - 1 = 1/2h2 + 2h + 3 ; Q: (2+h , 1/2h2 + 2h + 3)
mPQ = [ (1/2h2 + 2h + 3) - 1] / [ (2+h) - 2 ] = (1/2h2 + 2h + 2) / h = 1/2h + 2 + 2/h
mPQ | h=.5 = 6.25
Mahin I.
asked 01/25/22Let f(x)=1/2x2-1. Find slope mPQ of the secant line that contains points P=(2,f(2)) and Q=(2+h,f(2+h)) and then compute mPQ for h=0.5.
f(2) = 1/2(2)2 - 1 = 1 ; P: (2 , 1)
f(2 + h) = 1/2(2 + h)2 - 1 = 1/2h2 + 2h + 3 ; Q: (2+h , 1/2h2 + 2h + 3)
mPQ = [ (1/2h2 + 2h + 3) - 1] / [ (2+h) - 2 ] = (1/2h2 + 2h + 2) / h = 1/2h + 2 + 2/h
mPQ | h=.5 = 6.25
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