Math Homework Need Help

Question

Let f(x)=3x². Find the slope of the secant line containing the points (2,12) and (3,27).

Answer 1

The slope formula for secant line is same as slope of any line.

m_sec = Δx / Δy = y₂ - y₁ / x₂ - x₁

= 27-12 / 3-2

= 15/1

Here, the gradient is 15.

Answer 2

Hi Mahin,

The secant line is just the line that connects those two points that lie on the curve. So the slope is just

(27-12)/(2-1)