You have submitted the function incorrectly...you mean f(t)=4[cos(t)-1]/t2 for which the limit is, in fact, -2.
Roz A.
asked 01/24/22limits - calculus
Consider the function
h(t) = 4 cos (t) − 4/t2
a. Fill in the table below to look at the behavior neart = 0.
Enter UNDEFINED if the function is undefined.
Round answers to three decimal places.
t | h(t) |
1 | -1.839 |
0.5 | -1.959 |
0.1 | -1.998 |
0.01 | -1.9999 |
0 | UNDEFINED |
−0.01 | -1.9999 |
−0.1 | - |
−0.5 | - |
−1 | - |
b) Estimate the value of lim t→0 h(t) = _________
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