the height of an object is given by y(t) = 100t − 16t2

Question

the height of an object is given by y(t) = 100t − 16t2

with y in feet and t in seconds. Compute the velocity at the instant when t = 1.70 seconds. Your answer must be accurate to one decimal place.

dy

dt t=1.7 = _____________

Answer 1

v = y'(t) = 100-32t

v(1.7) = 100-32(1.7) = 100-54.4 = 45.6 ft/sec