If P(-3,33) is a point on f(x) find the equation of the secant line PQ. Given Q is a point on f(x) when x=4. f(x)=2x-3x^2

Answer 1

I think Mark M. may have misunderstood the question...or maybe I did.

Anyway f(-3)=-33 and f(4)=-40

The line between P and Q is simply (-40+33)/(4+3)=(y+33)/(x+3) which can be simplified and

"massaged" into any required form, e.g. y=-36-x.